please solve question fast emergency by herons formula
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question 6
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By phythagores theoram,
AC^2=AB^2+BC^2
10^2=6^2+BC^2
100=36+BC^2
100-36=BC^2
64=BC^2
square root of 64=BC
BC=8 cm
a=10cm
b=6cm
c=8cm
s=a+b+c/2
=10+6+8/2
=24/2
s=12cm
Area of triangle
=square root of (s-a)(s-b)(s-c) =square root of (12-10)(12-6)(12-8)
=square root of 2×6×4
=square root of 2×3×2×2×2
=2×2 square root of 3
=4 square root of 3
AC^2=AB^2+BC^2
10^2=6^2+BC^2
100=36+BC^2
100-36=BC^2
64=BC^2
square root of 64=BC
BC=8 cm
a=10cm
b=6cm
c=8cm
s=a+b+c/2
=10+6+8/2
=24/2
s=12cm
Area of triangle
=square root of (s-a)(s-b)(s-c) =square root of (12-10)(12-6)(12-8)
=square root of 2×6×4
=square root of 2×3×2×2×2
=2×2 square root of 3
=4 square root of 3
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