Physics, asked by Anushka0602, 10 months ago

please solve question
I'll Mark as brainiest and also tell how you solved it ​

Attachments:

Answers

Answered by dorgan399
36

Explanation:

11)

The last 3 resitances are in series ( resistance 1,2,3)

so there total resistance=3R

these 3 resistance is parllel to opposite( R resistance 4)

so their resistance is=1/(1/3R+1/R)=3R/4

Now the front 2 resistance(5&6) and the above resistance is in series

so Req=R+R+3R/4=11R/4

Attachments:
Similar questions