Question

please solve question
I will give 5 star and mark brainliest ​

Answer 1

the answer for this is 3/8

Answer 2

Step-by-step explanation:

Since we have given that

(\dfrac{9}{16}\times \dfrac{4}{12})+(\dfrac{9}{16}\times \dfrac{-3}{9})\\

We have to use the "Distributive law":

a×(b+c)=a×b+a×c

So, it becomes,

\frac{9}{16}(\frac{4}{12}-\frac{3}{9})\\\\=\frac{9}{16}\times (\frac{1}{3}-\frac{1}{3})\\\\=\frac{9}{16}(0})\\\\=0

Hence, Using distributivity, we get 0.