Question

please solve question in fig.​

Answer 1

$Let \: the\: number \:of \: rows = x$

$Number \:of \: students \:in \:one \:row = y$

$Total \: number \:of \: students = x \times y$

/*According to the problem given */

If one student is extra in a row , there will be 2 rows less

$Number \:of \: students \:in \:1 \:row = y + 1$

$Number \:of \:rows = x - 2$

$(x-2)(y+1) = xy$

$\implies x(y+1) - 2(y+1) = xy$

$\implies xy + x - 2y - 2 = xy$

$\implies x - 2y - 2 = 0$

$\implies x - 2y = 2 \: --(1)$

If 1 student is less in a row t would be 3 rows more .

$(y-1)(x+3) = xy$

$\implies y(x+3) - 1(x+3) = xy$

$\implies xy + 3y - x - 3 = xy$

$\implies 3y - x - 3 = 0$

$\implies - x + 3y = 3 \: --(2)$

/* Adding equations (1) and (2) , we get */

$\implies x - 2y - x + 3y = 2 + 3$

$\implies y = 5$

/* put y = 5 in equation (1) ,we get */

$x - 2\times 5 = 2$

$\implies x - 10 = 2$

$\implies x = 2 + 10$

$\implies x = 12$

$\red{ The \: number \:of \: students \:in \: the }\\\red{ class } = xy \\= 12 \times 5 \\\green {= 60}$

•••♪

Answer 2

hello bro

how are you

gst

goo night