Question

Please solve question in the attachment and with figure.

Answer 1

Answer:

⇒ Vertices = A(11,4), B(-4,3),C(3,2).

⇒ Area = 11 units.

Step-by-step explanation:

Consider a ΔABC with vertices as A(x₁,y₁),B(x₂,y₂) and C(x₃,y₃).

Given,D(-1/2,5/2),E(7,3) and F(7/2,7/2) are mid-points of BC, CA and AB.

The vertices of ΔABC = A(11,4), B(-4,3) and C(3,2).

The area of ΔABC = 11 units.

Hope it helps!