Question

please solve question no.12

Answer 1

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suppose that the angles are A and B
then A+B=80°..................................(1)
A-B=20°...................................(2)

by adding the equation 1 & 2
2A=100°
A=100°/2=50°

by putting the value in equation 1

A+B=80°
B=80°-50°=30°
therefore the A=50° & B=30°

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Answer 2

Question:

The sum of two angles of a triangle is 80° and their difference is 20°, find the angles of the triangle.

Answer:

Let the larger angle (in degree) = x

Let the smaller angle (in degree) = y

According to question

x + y = 80° (Equation 1)

x - y = 20° (Equation 2)

Adding Equation 1 and Equation 2

x + y + x - y = 80° + 20°

x + x = 100°

2x = 100°

x = $\dfrac{100^{\circ}}{2}$

x = 50°

Putting value in Equation 1

x + y = 80°

50° + y = 80°

y = 80° - 50°

y = 30°

Therefore, The angles of the triangle are 50° and 30°.