Question

please solve question no. 13​

Answer 1

Answer:

2πDC-[(AC×CB)/2]

Step-by-step explanation:

The area of circle -area of triangle= area of shaded region

Answer 2

Answer:

Step-by-step explanation:

area of triangle=1/2absinc

=1/2xy sin 90

=1/2xy

area of semi circle

=1/2 pie*r^2

r=ab/2= root( ac^2+bc^2) /2 =root (x^2+y^2) /2

area of semi circle

=1/2 pie*(x^2+y^2)/4

=pie*x^2+y^2 /8

=22/56 (x^2+y^2)

area of shaded part=area of semi circle - area of area of triangle

=22/56 (x^2+y^2) - 1/2xy