Please solve question no.17 I and ii
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1. sec∅ = cosec∅
sec∅ = sec(90-∅)
∅ = 90 - ∅
2∅ = 90
∅ = 45
2. tan∅ = cot∅
tan∅ = tan(90 - ∅)
∅ = 90 - ∅
2∅ = 90
∅ = 45
Anonymous:
Thanks
Answered by
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Answer:
The answer of the first question is 45° and the second answer is also 45°.
Step-by-step explanation:
- We all know that cosec∅ =sec( 90 - ∅ ) . Now we apply this formula in question number 1.
1. sec∅ = cosec∅
sec∅ = sec ( 90 - ∅ ) [ formula: cosec∅ =sec( 90 - ∅ ) ]
∅ = 90 - ∅
2∅ = 90
∅ = 45
- we also know that cot∅ = tan ( 90 - ∅ ) . now we are applying this formula in question number 2
2. tan∅ = cot∅
tan∅ = tan( 90 - ∅ ) [ formula: cot∅ = tan ( 90 - ∅ ) ]
]
∅ = 90 - ∅
2∅ = 90
∅ = 45
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