Math, asked by Anonymous, 1 year ago

Please solve question no.17 I and ii

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Answers

Answered by karthickshiva1015
1

1. sec∅ = cosec∅

   sec∅ = sec(90-∅)

   ∅ = 90 - ∅

   2∅ = 90

    ∅ = 45

2.  tan∅ = cot∅

     tan∅ = tan(90 - ∅)

      ∅ = 90 - ∅

      2∅ = 90

      ∅ = 45


Anonymous: Thanks
Answered by franktheruler
0

Answer:

The answer of the first question is 45° and the second answer is also 45°.

Step-by-step explanation:

  • We all know that cosec∅  =sec( 90 - ∅ ) . Now we apply this formula in question number 1.

1. sec∅ = cosec∅

    sec∅ = sec ( 90 - ∅ )        [ formula:  cosec∅  =sec( 90 - ∅ )  ]

   ∅ = 90 - ∅

   2∅ = 90  

    ∅ = 45

  • we also know that cot∅ =  tan ( 90 - ∅ ) . now we are applying this formula in question number 2

2.  tan∅ = cot∅

     tan∅ = tan( 90 - ∅ )     [ formula:  cot∅ =  tan ( 90 - ∅ ) ]

]

       ∅ = 90 - ∅

      2∅ = 90

      ∅ = 45

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