Question

please solve question no. 19,21(i),(ii) and (iii) ASAP​

Answer 1

Step-by-step explanation:

19) cosec theta- sin theta= a^3 and sec theta - cos theta= b^3

1. - sin theta = a^3

sin theta

cos^2 theta = a^3

sin theta

a =(cos ^2 theta/sin theta)^1/3

similarly b= (sin^2 theta/cos theta)^1/3

a^2b^2(a^2+b^2)= a^4b^2 + a^2b^4

(cos^2 theta/sin y)^2/3 (sin^2 theta/ cos theta)^4/3

(cos theta)^8/3-2/3*(sin theta)^4/3-4/3 + (sin theta)^8/3-2/3*(cos theta)4/3-4/3

cos^2 theta + sin^2 theta= 1

a^2b^2(a^2+b^2) = 1