Math, asked by VijayaLaxmiMehra1, 1 year ago

please solve question no. 2 and 3.

Class 10th

Content Quality Solution needed.

I will mark as a branliest one.

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Answers

Answered by RishabhBansal
3
Hey!!!

Method Source - RD

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Let's solve

Q2. Given

=> Zeros = -9 and -1/9

Let S = sum of Zeros
and P = product of zeros

thus

=> S = -9 - 1/9

=> S = -82/9

Similarly

=> P = -9(1/-9)

=> P = 1

Required Polynomial = k(x² - Sx + P)

Thus

=> k(x² + 82x/9 + 1)

 \frac{1}{9} (9 {x}^{2} + 82 + 9)

Thus the required Quadratic Polynomial is 9x² + 82 + 9

Q3. Given

=> S = 0

=> P = - √15

Required Polynomial = k(x² - Sx + P)

=> k(x² - √15)

Thus the required Quadratic Polynomial is x² - √15

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If you'll use this method in exam no one will deduct your marks, don't worry, you can add more style and content to this method

Hope this helps ✌️

Good Night :-)

VijayaLaxmiMehra1: in Qno. 2 in last answer is 9xsquare+82x+9 you have not write 82x
RishabhBansal: sorry corrected
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