Please solve question no 29
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this is the answer of your math
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kanhaiya6714:
Usko Hindi me karo na kon sa bhasha hai ham nahi samajh paa rahe hain
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Hey friend, Here is your answer-
Angle OBC = Angle OCB......... (Angle inscribed in same arc )
Therefore Angle OCB = 25°
In Triangle OBC ,
Angle OBC + OCB + BOC = 180°
25° + 25° + Angle BOC = 180°
50° + Angle BOC = 180°
Angle BOC = 180° - 50°
Angle BOC = 130°
Angle BOC = m (arc BC)
Therefore m(arc BC) = 130°
Angle BAC = 1/2 m (arc BC)
Angle BAC = 1/2 × 130
Angle BAC = 65°
Hope it will help you.
Please make me brainliest
Angle OBC = Angle OCB......... (Angle inscribed in same arc )
Therefore Angle OCB = 25°
In Triangle OBC ,
Angle OBC + OCB + BOC = 180°
25° + 25° + Angle BOC = 180°
50° + Angle BOC = 180°
Angle BOC = 180° - 50°
Angle BOC = 130°
Angle BOC = m (arc BC)
Therefore m(arc BC) = 130°
Angle BAC = 1/2 m (arc BC)
Angle BAC = 1/2 × 130
Angle BAC = 65°
Hope it will help you.
Please make me brainliest
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