please solve question no. 2nd
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if 3 is zero of polynomial ,then p(x)=0
√[(3)^2-4(3)+3] + √[(3)^2-9] - √[4(3)^2-14(3)+6]
√[9-12+3] + √9-9 - √[36-42+6]
0+0+0 =0
hence 3 is zero of polynomial
√[(3)^2-4(3)+3] + √[(3)^2-9] - √[4(3)^2-14(3)+6]
√[9-12+3] + √9-9 - √[36-42+6]
0+0+0 =0
hence 3 is zero of polynomial
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Hello! !!!!
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# Nikky
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see the attachment
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# Nikky
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