Please solve question no 3.
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Let tens digit of number is X
.......Unit digit ........................ is Y
Now Number = X×10 +Y
If digits are reversed
New Number = 10Y+X
ATQ
X-Y= 6.......1
(10X+Y )+ (10Y+X) =110
11X+11Y=110
X+Y= 10 ......................2
Subtracting eq 2 from eq1
X-Y=6
X+Y= 10
2X=16
X=8
Y=8-6
Y=2
SO
The Number is 8×10 +2 = 82
Answer---82
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