Question

please solve question no.36

Answer 1

Hope this helps u Please make me as a brainliest

Answer 2

☆hey friend!!!☆

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Here is your answer ☞
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$given \\ \\ {2}^{x} = {4}^{y} = {8}^{z } \\ \\ = > \: {2}^{ \ x} = {2}^{2y} = {2}^{3z } \\ \\ so \\ \\ = > \: x \: = 2y = 3z \\ \\ now \\ \\ = > \: \frac{1}{2x} + \frac{1}{4y} + \frac{1}{4z} = 4 \\ \\ plug \: th e \: value \: we \: get \\ \\ = > \: \frac{1}{2x} + \frac{1}{2x} + \frac{3}{4x} = 4 \\ \\ = > \frac{2 + 2 + 3}{4x} = 4 \\ \\ = > \: 16x = 7 \\ \\ hence \\ \\ = > \: x = \frac{7}{16} .........answer$

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Hope it will help you ☺☺
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Devil_king ▄︻̷̿┻̿═━一