Question

Please solve question no. 4

Answer 1

I HAVE DENOTED UNDER ROOT BY THIS SYMBOL "#"

COT²-(1+#3)COT-#3=0

COT²-COT-#3COT+#3=0

COT(COT-1)-#3(COT-1)

(COT-#3)(COT-1)=0

CASE 1

COT=#3

TAN=1/#3

TAN=TAN PI/6

X=N×PI+PI/6

CASE2

COT=1

TAN=1

TAN=TAN PI/4

X=N×PI+PI/4