Question

Please solve question no 4

Answer 1

Answer:

Step-by-step explanation:

X= 8

5x-4/8 - x-3/5 = x+6/5

5(8) -4 /8 - 8-3/5. = 8+6/5

40-4 / 8. - 5/5 = 14/5

36/8 -1 = 14/5

36-8÷8 = 14/5

28/8 = 14/5

14/4 ≠ 14/5

Answer 2

   

$\frac{5x-4}{8}-\frac{x-3}{5}=\frac{x+6}{5} \\ \\ \\ \frac{5(5x-4)-8(x-3)}{8 \times 5}=\frac{x+6}{5} \\ \\ \\ \frac{25x-20-8x+24}{40}=\frac{8(x+6)}{8 \times 5} \\ \\ \\ \frac{17x+4}{40}=\frac{8x+48}{40} \\ \\ \\ 17x+4=8x+48 \\ \\ \\ 17x-8x=48-4 \\ \\ \\ 9x = 44 \\ \\ \\ x \ = \ \frac{44}{9} \ \neq \ 8$

Hence verified that x = 8 is not a solution.

But there's no need of this method. What about putting the value of x in the question as 8 and then checking?!

Letting x = 8,

$\frac{5x-4}{8}-\frac{x-3}{5}=\frac{x+6}{5} \\ \\ \\ \frac{5 \times 8-4}{8}-\frac{8-3}{5}=\frac{8+6}{5} \\ \\ \\ \frac{40-4}{8}-\frac{8-3}{5}=\frac{8+6}{5} \\ \\ \\ \frac{36}{8}-\frac{5}{5}=\frac{14}{5} \\ \\ \\ 4\frac{1}{2}-1=2\frac{4}{5} \\ \\ \\ 3\frac{1}{2} = 2\frac{4}{5}$

Okay, a contradiction occurred.

Hence verified!

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Thank you. :-))