Question

Please solve question no.7

Answer 1

Hello user

x = a.sin○ and y = b.tan○

Squaring both of them we get...

x^2 = a^2.sin^2○

x^2/a^2 = sin^2○ ........(1)

Similarly, we get

y^2/b^2 = tan^2○ ...........(2)

Subtracting eq. 1 and 2 by reprocaling them,
we get..

a^2/x^2 - b^2/y^2 = 1/sin^2○ - 1/tan^2○
= (1-cos^2○)/(sin^2○)

since, 1-cos^2○ = sin^2○

So,

a^2/x^2 - b^2/y^2 = (sin^2○)/(sin^2○) = 1


Hence proved

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