Question

Please solve question no. 7
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Answer 1

Answer:

Veer's Monthly Income is Rs.6500

Explanation:

Let Veer's monthly income be x

Since, he spends 15% of his income on house rent,

therefore

15% of x

$= \frac{15 \times x}{100} \\= \frac{3x}{20}$

So, remaining amount left

$= x - \frac{3x}{20} \\ = \frac{20x - 3x}{20} \\ = \frac{17x}{20}$

Therefore, on household expenditure, he spends

$60\%of \frac{17x}{20} \\ = \frac{60 \times 17x}{20 \times 100} \\ = \frac{51x}{100}$

Now, remaining amount left with him

$= \frac{17x}{20} - \frac{51x}{100} \\ = \frac{85x - 51x}{100} = \frac{34x}{100} = \frac{17x}{50}$

So,

According to the problem,

$\frac{17x}{50} = 2210 \\ = > 17x = 50 \times 2210 \\ = > x = \frac{50 \times 2210}{17} \\ = > x = 130 \times 50 \\ = > x = 6500$

Hence, Veer's Monthly Income is Rs.6500

_____________________________________

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Answer 2

Given:

• 15 % expenditure is on house rent
• 60 % expenditure is on other household needs
• Money saved = Rs. 2210.

Solution:

Let the monthly income of Veer be x

House rent = 15% of x

                   =  $\frac{15}{100}$ × x

                   = $\frac{15x}{100}$

Money left = $x-\frac{15x}{100}$

Money spent on household = 60% of( $x-\frac{15x}{100}$)

= $\frac{60}{100}$ ×( $x-\frac{15x}{100}$)

According to the Question:

$x-\frac{15x}{100}$ + $\frac{60}{100}$ × ($x-\frac{15x}{100}$) + 2210 = x

⇒$\frac{85x}{100}$ + $\frac{60}{100}$ × $\frac{85x}{100}$ + 2210 = x

⇒ $\frac{85x}{100}$ + $\frac{5100x}{10000}$ + 2210 = x

⇒$\frac{13600x}{10000}$ + 2210 = x

⇒ $\frac{13600x}{10000}-x$ = -2210

⇒$\frac{13600x-10000x}{10000}$ = - 2210

⇒$\frac{3600x}{10000}$ = - 2210

⇒x = $\frac{-2210}{3600}$ × 100 × 100

⇒ x = Rs. 6138.88

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