Question

please solve question no. 8th please do it. From Chapter-2 Polynomial.

Class 10th

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Answer 1

★ Hi , there !!★


here is your answer !!!


3 is zero of polynomial so. ,

on putting the value of zeroes in polynomial we get !!


2x² - 3 x + p = 0


2 ( 3 )² - 3 × 3 + p = 0


2× 9 - 9 + p = 0


18 -9 + p = 0


p= -9


hope it helps you dear !!!



thanks !!!

Answer 2

Given f(x) = 2x^2 - 3x + p.

Given that one of the zero of the Quadratic polynomial is 3.

f(3) = 0

= > f(2) = 2(3)^2 - 3(3) + p = 0

            = 18 - 9 + p = 0

            = 9 + p = 0

            p = -9.


Now,

= > 2x^2 - 3x - 9

= > 2x^2 - 6x + 3x - 9

= > 2x(x - 3) + 3(x - 3)

= > (2x + 3)(x - 3)

= > x = 3, -3/2.


Therefore the other zeroes are 3,-3/2.


Hope this helps!