please solve question no (d)
please i need help
Answers
Answer:
First if you want to prove that altitude of equilateral triangle = √3/2 × a, you can apply Pythagoras Theorem in ∆PQM where PQ= a and QM= a/2 , since altitude of equilateral triangle divides the base into two equal halves.
ST= 10cm
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Step-by-step explanation:
Area of trapezium= Area of rectangle+Area of
triangle
Area of trapezium = 175√3cm^2
Area of rectangle = Length×Breadth = ST×TQ
Area of triangle= (√3/4)a^2 = (√3/4)×PQ^2
ST = PQ. (Opposite sides of rectangle are equal to each other)
(ST × 3ST ) + (√3/4)× ST^2 = 175√3
[ Given PQ = 3ST]
3ST^2 + ( 1.73/4)×ST^2 = 175 × 1.73 ( √3=1.73)
3ST^2 + 0.43 × ST^2 = 302.75
3ST^2 + 0.43 ST^2 = 302.75
3.43 ST^2 = 302.75
ST^2 = 302.75/ 3.43
ST = √88.26
ST = 9.39cm Answer