Math, asked by Kanhaiyabhumihar, 11 months ago

Please solve question no vii of 2

Attachments:

Kanhaiyabhumihar: all those who is bhumihar please follow me i will also follow you
rcagindiap9s19c: Which book is this ?
Kanhaiyabhumihar: Rd Sharma
Kanhaiyabhumihar: class- 9
rcagindiap9s19c: Cost ?
Kanhaiyabhumihar: rs 1000
rcagindiap9s19c: Shall I answer your question no one is doing so
Kanhaiyabhumihar: no i have done
rcagindiap9s19c: Answer ?
Kanhaiyabhumihar: 175

Answers

Answered by rcagindiap9s19c
1

Answer:175

Step-by-step explanation:

(5^{-1-2} * 7^{2-(-4)})^{7/2} *( 5^{-2-3} * 7^{3-(-5)} )^{-5/2}\\ = (5^{-3}*7^{6})^{7/2}*(5^{-5}*7^{8})^{-5/2}\\=(5^{-3*7/2}* 7^{6*7/2})*(5^{-5*-5/2}*7^{8*-5/2} \\=(5^{ -21/2 }*7^{21})*5^{25/2}*7^{ -20 } \\= (5^{-21/2 + 25/2}*7^{21 + (-20)} \\= 5^{2}*7^{1} \\=25*7\\=175


Kanhaiyabhumihar: Thanks
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