please solve question no8
Attachments:
Answers
Answered by
3
Answer:
Step-by-step explanation:
AP = AS
BP = BQ
CR = CQ
DR = DS
( Tangents from external point are in equal lengths )
By adding :-
AP + BP + CR+ DR = AS+ DS + CQ+ BQ
AB + CD = AD + BC
Hence Proved
Answered by
1
solution: AP and AS are two tangents drawn from external point a to a circle.
AP=AS...(1)
BP=BQ...(2)[ length of tangents drawn from an external point a two circle are equal]
CQ=CR....(3)
DR=DS....(4)
ADD equation (1),(2),(3)AND(4)
AP+BP+CR+DR=AS+BQ+CQ+DS
(AP+BP)+(CR+DR)=(AS+DS)+(BQ+CQ)
AB+CD=AD+BC
HENCE PROVED
AP=AS...(1)
BP=BQ...(2)[ length of tangents drawn from an external point a two circle are equal]
CQ=CR....(3)
DR=DS....(4)
ADD equation (1),(2),(3)AND(4)
AP+BP+CR+DR=AS+BQ+CQ+DS
(AP+BP)+(CR+DR)=(AS+DS)+(BQ+CQ)
AB+CD=AD+BC
HENCE PROVED
Similar questions