please solve question Number 17
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Mass of AgCl = 0.7134
Moles of AgCl = 0.7134/143.5 = 0.0049
Moles of AgCl = Moles of Cl- in the sample = 0.049.
Mass of Cl- in the sample = 0.0049*35.5 = 0.176
%Cl- = 0.176/0.6025 = 29.21%
Moles of AgCl = 0.7134/143.5 = 0.0049
Moles of AgCl = Moles of Cl- in the sample = 0.049.
Mass of Cl- in the sample = 0.0049*35.5 = 0.176
%Cl- = 0.176/0.6025 = 29.21%
abhirajpathak9:
corrected bro
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