Question

please solve question number 29 to 34 please solve in your notebook and then you click a picture and post it here then I'll make him or her brain list please solve this

Answer 1

i can solve any one of them so just choose one.....

Answer 2

here is your answer
29)
$\frac{ {2}^{36} + {2}^{37} + {2}^{38} }{ {2}^{39} + {2}^{38} + {2}^{37} } \\ \\ \frac{ {2}^{36} ( {2}^{0} + {2}^{1} + {2}^{2} ) }{ {2}^{37} ( {2}^{2} + {2}^{1} + {2}^{0} )} \\ \\ \frac{ {2}^{36} (1 + 2 + 4)}{ {2}^{37} (4 + 2 + 1)} \\ \\ \frac{ {2}^{36} \times 7 }{ {2}^{37} \times 7} \\ \\ \frac{ {2}^{36} }{ {2}^{37} } \\ \\ {2}^{(36 - 37)} \\ {2}^{( - 1)} \\ \\ = \frac{1}{ {2}^{1} } = \frac{1}{2}$

29)ii)
$(( {64}^{ \frac{1}{2} } {)}^{ \frac{1}{6} } {)}^{ 2} \\ \\( {8}^{ \frac{1}{6} } {)}^{2} \\ \\ {8}^{( \frac{1}{6} \times 2)} = {8}^{ \frac{1}{3} } \\ = (2 \times 2 \times 2 {)}^{ \frac{1}{3} } \\ 2 \: answer$

30)
$\frac{6}{3 \sqrt{2} - 2 \sqrt{3}} = 3 \sqrt{2} - a \sqrt{3} \\ \\ \frac{6}{ 3\sqrt{2} - 2 \sqrt{3} } \times \frac{3 \sqrt{2} + 2 \sqrt{3} }{3 \sqrt{2} + 2 \sqrt{3} } \\ \\ \frac{6(3 \sqrt{2} + 2 \sqrt{3}) }{ {(3 \sqrt{2} )}^{2} - (2 \sqrt{3} {)}^{2} } \\ \\ \frac{6(3 \sqrt{2} + 2 \sqrt{3} ) }{18 - 12} \\ \\ \frac{6(3 \sqrt{2} + 2 \sqrt{3} )}{6} \\ \\ 3 \sqrt{2} + 2 \sqrt{3} = 3 \sqrt{2} - a \sqrt{3} \\ 2 \sqrt{3} = 3 \sqrt{2} - a \sqrt{3} - 2 \sqrt{3} \\ 2 \sqrt{3} = - a \sqrt{3} \\ a \sqrt{3} = - 2 \sqrt{3} \\ a = \frac{ - 2 \sqrt{3} }{ \sqrt{3} } \\ \\ a = - 2$

here is your answer
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