Please solve question number 5 and 7
Attachments:
Answers
Answered by
1
hope it helps you!!!!!!!
Attachments:
Answered by
2
for ques 5
if all the sides are 30 and the longer diagnol is 48 then the shorter one would be 36.
( use the Pythagoras because diagnols of a rhombus cuts each other at 90 degrees and bisects them equally, so hypotenuse being 30 and base being 48/2=24 the perpendicular side would be 18 and the whole diagnol would be 18 x 2=36)
now when u know each parameter the area of the rhombus would be
1/2 x 24 x 18(area of one right-angle triangle) x 4( because there are 4 of them)
and now devide by 18 as there are 18 cows.
1/2 ( 24 x 18 x 4)/18=48
answer 48 meter sqr
if all the sides are 30 and the longer diagnol is 48 then the shorter one would be 36.
( use the Pythagoras because diagnols of a rhombus cuts each other at 90 degrees and bisects them equally, so hypotenuse being 30 and base being 48/2=24 the perpendicular side would be 18 and the whole diagnol would be 18 x 2=36)
now when u know each parameter the area of the rhombus would be
1/2 x 24 x 18(area of one right-angle triangle) x 4( because there are 4 of them)
and now devide by 18 as there are 18 cows.
1/2 ( 24 x 18 x 4)/18=48
answer 48 meter sqr
Similar questions