Math, asked by rajanushka24877, 11 months ago

Please solve question number 5...... I will mark you as the brainliest.......... Please please please please solve this fast.....

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Answers

Answered by gaurav2013c
3
Let the numerator be a

Denominator = 2a + 1

Fraction = a / (2a + 1)

According to question,

a / (2a + 1) + (2a+1) / a = 2 16 /21

=> [ a^2 + (2a+1)^2] / a(2a +1) = 58 /21

=> ( a^2 + 4a^2 + 4a + 1) / (2a^2 + a) = 58 /21

=> ( 5a^2 + 4a + 1) / (2a^2 + a) = 58 /21

=> 105a^2 + 84a + 21 = 116a^2 + 58a

=> 11a^2 - 26a - 21 = 0

=> 11a^2 - 33a + 7a - 21 = 0

=> 11a ( a - 3) + 7 ( a - 3) = 0

=> (a-3) (11a + 7) = 0

a = 3 and - 7 /11


Neglecting negative value, we get

a = 3

Required fraction = 3 / (2 × 3 + 1)

= 3 / 7
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