Question

please solve question number 9 and 11. it's very urgent..

Answer 1

Question 9

First note that 30-22=8

and $2^3=8$

So 2 is linked.

Second 67-40=27

$3^3=27$

Hence it is 3

Lat one:-

416-200=216.

$6^3=216$

So the answer will be 6.

Answer:-6(option{1})

Question 11

Good trick.

9*7=(9+7)(9-7)

=16*2=32

Next:11*5=(11+5)(11-5)

=16*6

=96.

The answer will be:

17*9=(17+9)(17-9)

=26*8

=208.

Answer:208(option{3})

Hope I helped you.

Answer 2

Hi there !
Here's the answer:

•°•°•°•°•<><><<><>><><>•°•°•°•°•°

10.
Given,
22 - 30 - ( 2 )
40 - 67 - ( 3 )
200 - 416 - ( ? )

The last or below letter relation to above or the other two Numbers is
CUBE ROOT OF THEIR DIFFERENCES .

Viz.,
¶ 30-22= 8 & cuberoot(8) = 2
This is first lower No.

¶ 67 - 40 = 27 & cuberoot(27) = 3
This is second lower No

¶ 416 - 200 = 216
& Cuberoot(216) = 6
This is (?) third lower No .

•°• 6 is th Answer for 10th question
This answer exists in option (1).

•°•°•°•°•<><><<><>><><>•°•°•°•°•°

11.

¶ 9*7 = 32
=> (9+7)(9-7) = 16×2 = 32

¶ 11*5 = 96
=> (11+5)(11-5) = 16 × 6 = 96

¶ 17*9 = ?
= (17+9)(17-9) = 26 × 8 = 208.

•°• 208 is the answer.
This is in option (3)

•°•°•°•°•<><><<><>><><>•°•°•°•°•°

¢#£€®$

:)

Hope it helps