Question

please solve QUESTIONS NO. 8
correctly ​

Answer 1

Given that,

length, l = 4.234 m

breadth,b = 1.005 m

thickness, t = 2.01 cm = 2.01 × 10-2 m

Area of the sheet = 2 (l × 0 + b × t + t × l) = 2 (4.234 × 1.005 + 1.005 × 0.0201 + 0.0201 × 4.234)

= 2 (4.3604739) = 8.7209478 m2

As area can contain a maximum of three significant digits, therefore, rounding off, we get

Area = 8.72 m2

Also, volume = l × b × t

V = 4.234 × 1.005 × 0.0201 = 0.0855289 = 0.0855 m3 (Significant Figures = 3)

hope it helps you ❤️

Answer 2

I hope it will helpfull for you