please solve questions no 9 10 11 12 ....
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1
q no.12 (A'C) square=(A'B)sq+(BC)sq
(A'C)sq= 24sq+7sq.
= 576+49.
=625
A'C=
![\sqrt{625 = 25} \sqrt{625 = 25}](https://tex.z-dn.net/?f=+%5Csqrt%7B625+%3D+25%7D+)
AB=AC+BC.
=(25+7).
=32
(A'C)sq= 24sq+7sq.
= 576+49.
=625
A'C=
AB=AC+BC.
=(25+7).
=32
Answered by
1
mark it as brainliest
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