please solve questions........urgent please solve question no. 32
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dimension of frustum shaped bucket:
radius of the lower end=8cm
radius of the upper end=20cm
height=16cm
∴ slant height=√h²+(R-r)²
=√16²+(20-8)²
=√256+144
=√400
=20cm
TSA of the bucket=πl(R+r)+πr²
=3.14×20(20+8)+3.14×8²
=1758.4+200.96
=1959.36cm²
rate of metal sheet=Rs 15 per 100cm²
∴cost of metal sheet used for the bucket
=Rs 15×1959.36/100
=Rs 15×19.5936
=Rs 293.904
volume of the bucket=1/3πh(R²+r²+R×r)
=1/3×3.14×16(400+64+160)
=1/3×3.14×9984
=10449.92cm³
rate of milk=Rs 16 per litre
∴cost of milk which can completely fill the bucket
=16×10449.92/1000
=167.19872 Rs (roundly 167.20 Rs)
radius of the lower end=8cm
radius of the upper end=20cm
height=16cm
∴ slant height=√h²+(R-r)²
=√16²+(20-8)²
=√256+144
=√400
=20cm
TSA of the bucket=πl(R+r)+πr²
=3.14×20(20+8)+3.14×8²
=1758.4+200.96
=1959.36cm²
rate of metal sheet=Rs 15 per 100cm²
∴cost of metal sheet used for the bucket
=Rs 15×1959.36/100
=Rs 15×19.5936
=Rs 293.904
volume of the bucket=1/3πh(R²+r²+R×r)
=1/3×3.14×16(400+64+160)
=1/3×3.14×9984
=10449.92cm³
rate of milk=Rs 16 per litre
∴cost of milk which can completely fill the bucket
=16×10449.92/1000
=167.19872 Rs (roundly 167.20 Rs)
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