Question

please solve quickly ?????​

Answer 1

Solution:-

4p + 3q = 14 .......(i)eq

3p - 4q = 23 ........(ii) eq

Substitute the (i)st equation, we get

4p + 3q = 14

4p = 14 - 3q

$p = \frac{14 - 3q}{4} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: ( \bf \: i ii\:)eq$

Now put the value of p on (ii) eq we get

$3( \frac{14 - 3q}{4} ) - 4q = 23$

$\frac{42 - 9q}{4} - 4q \: = \: 23$

Take a lcm

$\frac{42 - 9q - 16q}{ 4} = 23$

Use cross multiplication, we get

$42 - 25q = 92$

$- 25q = 50$

$q = \frac{ - 50}{25}$

$q = - 2$

Now put the value of q on i st equation

4p + 3q = 14

4p + 3 × ( - 2) = 14

4p - 6 = 14

4p = 20

p = 5

Answer:- p= 5 and q = - 2