Question

please solve really urgently please ​

Answer 1

Answer:

The value of $\frac{1-sin^{2}45^{o}}{1+sin^{2}45^{o}}$ is $tan^{2}30^{o}$.

Step-by-step explanation:

Let u = $\frac{1-sin^{2}45^{o}}{1+sin^{2}45^{o}}$

⇒ u = $\frac{1-(\frac{1}{\sqrt{2}})^{2}}{1+(\frac{1}{\sqrt{2}})^{2}}$

or u = $\frac{1-\frac{1}{2}}{1+\frac{1}{2}}$

or u = $\frac{2-1}{2+1}$

or u = $\frac{1}{3}$

⇒ u = $tan^{2}30^{o}$