Please solve sec c and d
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which question I have to solve
Given :- Dimensions of Room =7.5mX6mX3.75m
The longest rod that can measure = Diagonal of Room
= \sqrt{l^{2} + b^{2} + h^{2} }=
l
2
+b
2
+h
2
= \sqrt{7.5 {}^{2} + 6 {}^{2} + 3.75 }=
7.5
2
+6
2
+3.75
= \sqrt{56.25 + 36 + 14.06}=
56.25+36+14.06
= \sqrt{106.31}=
106.31
= 10.31m=10.31m
Hope it helps you mark as brainliest please
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