Please solve second one and explain
Attachments:
Answers
Answered by
0
cos A = √3 /2
sin A = 1 /2
cotA = sinA / cos A
= (1 /2)/( √3 /2 )
= 1 /√3
secA = 1 /cosA
= 1 /(√3 /2)
= 2 / √3
hope it helps !
thank you !
sin A = 1 /2
cotA = sinA / cos A
= (1 /2)/( √3 /2 )
= 1 /√3
secA = 1 /cosA
= 1 /(√3 /2)
= 2 / √3
hope it helps !
thank you !
Similar questions