Question

please solve step by step​

Answer 1

Step-by-step explanation:

HERE,WE HAVE

CF=BD

BF-CF=BF-BD

BC=DF

NOW,

IN TRIANGLE ABC AND TRIANGLE EDF,WE HAVE

AC=DE

LBAC=LDEF=90°

AND,BC=DF (PROVED ABOVE)

THEREFORE, TRIANGLE ABC IS CONGRUENT TO TRIANGLE EDF BY RHS CONGRUENCE RULE.

HOPE IT HELPS YOU ☺.