Question

Please Solve Step by Step

Answer 1

An archery target has three concentric regions.The diameter of the regions are in ratio 1:2:3.?

Ratio of their Areas?

Solution,

diameters to be= k, 2k, 3k.  

radius would be,  k/2, k, 3k/2  

B1= central circle's are  = (pi)*k^2/4  

B2=next region area = pi *(k^2 - k^2/4) = (3/4)*pi*k^2  

B3= outermost region area = pi *(9k^2/4 - k^2) = (5/4)pi*k^2  

required ratio would be B1:B2:B3

= (pi)*k^2/4  :(3/4)*pi*k^2  : (5/4)pi*k^2  

Ratios of their areas ===> 1:3:5