Question

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Answer 1

Answer:

3. a^2+16a+k

a^2+2×8×a+k

for perfect square k=64

as a^2+16a+64=(a+8)^2

k=64

Answer 2

Answer:

1.64

2.0

Step-by-step explanation:

1. a^2+ 16a+ k

a^2+2(a)(8)+k

so we see that it looks like formula no. 1

x^2+2xy+y^2= (x+y)^2

so,a^2+2(a)(8)+8^2

(a+8)^2

so,k=8^2

k=64

2. if

2.If

$x+\frac{1}{x}=2$

take x as LCM

$\frac{ {x}^{2}+1 = 2x}{x}$

cancle x from denominator

so, x^2+1=2x is the new equation

by shifting

x^2-2x+1=0

now it's look alike formula no.2

a^2-2ab+b^2= (a-b)^2

(x-1)^2

so,x-1=0

x=1

by putting the value of x in equation

${x}^{2013} - \frac{1}{ {x}^{2012} }$

so,1^2013-1/1^2012

1-1/1

1-1=0