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In the given figure, O is the centre of the circle of radius 6 cm. If PA and PB are two chords each of length 8 cm, then the length of chord AB is
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From O, draw OD⊥AB
AB=AP+PB=4+5=9cm
⇒ AD=4.5cm
In right △OAD,
OD=
OA
2
−AD
2
=
6
2
−4.5
2
=
36−20.25
=
15.75
PD=AD−AP=4.5−4=0.5cm
In right △OPD,
OP=
OD
2
+PD
2
=
15.75+0.5
2
=
15.75+0.25
=
16
=4cm
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