Question

Please solve step by step

Thanks in advance

Answer 1

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Here's your answer...

Let the digits be x and y.
x+y = 7 --> x = 7-y

10y+x+3 = 4(10x+y)
10y+x+3 = 40x+4y
39x-6y = 3
13x-2y = 1
13(7-y) - 2y = 1
91 - 13y - 2y = 1
15y = 90
y = 6
x+6 = 7
x = 1

The number is 16.

Verification:
1+6 = 7
61 + 3 = 4×16

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Answer 2

Answer:

16

Step-by-step explanation:

Let tens digit and units digit of the number be x and y.

x + y = 7   ----- (i)

The two digit number is 10x + y.

The two digit number when reversed becomes 10y + x.

According to the given condition,

⇒ 10y + x + 3 = 4(10x + y)

⇒ 10y + x = 4(10x + y) - 3

⇒ 10y + x = 40x + 4y - 3

⇒ 39x - 6y = 3

⇒ 13x - 2y = 1     ----- (2)

On solving (i)*2 & (2), we get

⇒ 2x + 2y = 14

⇒ 13x - 2y = 1

   --------------------

    15x = 15

        x = 1.

Substitute x = 1 in (i), we get

x + y = 7

1 + y = 7

y = 6

Therefore, original number = 10x + y

                                             = 10(1) + 6

                                             = 16.

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