please solve sum 15 first part, I mark as brianliest
Attachments:
Answers
Answered by
0
(a)^3+ (-2b)^3 + (4c)^3 - 3(a)(-2b)(4c) = (a-2b+4c)(a^2+ 4b^2 + 16c^2 + 2ab + 8bc - 4ab)
Answered by
0
a3 + b3 + c3 - 3abc = (a + b + c)(a2+ b2 + c2 - ab - bc - ca)
using this formula ,
we have the required answer
i.e = (a-2b+4c)(a^2+4b^2+16c^2+2ab+8bc-4ca)
using this formula ,
we have the required answer
i.e = (a-2b+4c)(a^2+4b^2+16c^2+2ab+8bc-4ca)
Similar questions