Question

please solve sum no 11

Answer 1

Since (x-2) is a factor of polynomial kx^2-3x+k .so
let p (x) = kx^2-3x+k
p (2) =0
k (2)^2-3×2+k= 0
4k-6+k =0
5k=6
k=6/5 is the right answer

Answer 2

$\bf \LARGE \it Hey \: User!!!$

given :-

p(x) = kx² - 3x + k

g(x) = x - 2
>> x - 2 = 0
>> x = 2

on putting values :-

p(2) = k(2)² - 3(2) + k = 0
>> 4k - 6 + k = 0
>> 4k + k = 6
>> 5k = 6
>> k = 6/5

hence the value of k is 6/5

$\bf \LARGE \it Cheers!!!$