Question

Please solve:-
$\frac{3 - 4x}{9} - \frac{3x - 2}{3} = 2 \times \frac{1}{9} - \frac{ \times }{3}$
Please answer my question...​

Answer 1

Answer:

Step 1.Use grouping to factorise the numerator and take out the common factor \(ax\) in the denominator\[\frac{\left(ax - ab\right) + \left(x - b\right)}{a{x}^{2} - abx} = \frac{a\left(x - b\right) + \left(x - b\right)}{ax\left(x - b\right)}\]

Step 2.Take out common factor \(\left(x-b\right)\) in the numerator\[=\frac{\left(x - b\right)\left(a + 1\right)}{ax\left(x - b\right)}\]

Step 3.Cancel the common factor in the numerator and the denominator to give the final answer\[= \frac{a + 1}{ax}\]

Step-by-step explanation:

Hope it helps you dear.....