Question

please solve
thank you ​

Answer 1

Answer:

0

Step-by-step explanation:

0 because 1+1-2=0 so ans is zero

Answer 2

Required Answer:-

Given to Evaluate:

• $\rm \dfrac{ \cot(54 \degree) }{ \tan(36\degree)} + \dfrac{ \tan(20 \degree) }{ \cot(70 \degree) } - 2$

Solution:

This question can be solved by using Complementary angle formula.

Let's Know the formula.

$\rm \star \tan(90 \degree - \alpha ) = \cot( \alpha )$

$\rm \star \cot(90 \degree - \alpha ) = \tan( \alpha )$

We shall use this formula to evaluate the expression.

Let's start.

We have.

$\rm \dfrac{ \cot(54 \degree) }{ \tan(36\degree)} + \dfrac{ \tan(20 \degree) }{ \cot(70 \degree) } - 2$

Can be written as,

$\rm = \dfrac{ \cot(90 \degree - 36 \degree) }{ \tan(36\degree)} + \dfrac{ \tan(90 \degree - 70 \degree) }{ \cot(70 \degree) } - 2$

Now, applying the formula, we get,

$\rm = \dfrac{ \tan(36 \degree) }{ \tan(36\degree)} + \dfrac{ \cot(70 \degree) }{ \cot(70 \degree) } - 2$

Cancelling out the terms, we get,

$\rm = 1 + 1 - 2$

$\rm = 2 - 2$

$\rm = 0$

Hence,

$\rm \star \: \: \dfrac{ \cot(54 \degree) }{ \tan(36\degree)} + \dfrac{ \tan(20 \degree) }{ \cot(70 \degree) } - 2 = 0$

Answer:

• $\rm \dfrac{ \cot(54 \degree) }{ \tan(36\degree)} + \dfrac{ \tan(20 \degree) }{ \cot(70 \degree) } - 2 = 0$