Question

please solve that triganomatry problem....​

Answer 1

Step-by-step explanation:

GIVEN,

$\frac{ \cos(37) + \sin(37) }{ \cos(37) - \sin(37) }$

$= \frac{ \cos(90 -53) + \sin(37) }{ \cos(90 - 53) - \sin(37) }$

$= \frac{ \sin(53) + \sin(37) }{ \sin(53) - \sin(37) }$

$= \frac{2 \sin( \frac{53 + 37}{2}) \cos( \frac{53 - 37}{2} ) }{2 \sin( \frac{53 - 37}{2} ) \cos( \frac{53 + 37}{2} ) }$

$= \frac{ \sin(45) \cos(8) }{ \sin(8) \cos(45) }$

$= \tan(45) \cot(8)$

$= 1 \times \cot(</strong><strong>8</strong><strong>)$

$= \cot(</strong><strong>8</strong><strong>)$

HOPE THAT HELPS!!