Please solve the 19th question...please
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here's your answer ..
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We will take MTH term as a+(m-1)d and nth term as a+(n-1)d
ATQ n*nth term=m*Mth term
n(a+(n-1)d )= m(a+(m-1)d )
By solving this further you will get the answer as ...
a+md=0
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