Question

please solve the 2 question. please ​

Answer 1

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Given that,

In ∆ ABC

A + B = 75° ...... eqn(1)

also,

given

B + C = 150°

C = 150° - B ..... eqn(2)

now,

as we know by angle sum property

A + B + C = 180°

(using eqn(2))

A + B + 150° - B = 180°

A = 180° - 150° = 30°

putting value of A in eqn (1)

A + B = 75°

30 ° + B = 75°

B = 75° - 30°

B = 45°

Hence,

angle A = 30°

and

angle B = 45° .

Answer 2

Answer:

Given that,

in ∆ABC, A+B=75°

B=75°-A——eq-1

B+C=150°

B=150°-C——eq-2

from eq-1 & eq2, both LHS are equal.

75-A=150-C

-A+C=150-75

C-A=75°

C=75-A——eq3

substitute eq3 in eq2

B=150-(75-A)

B=150-75+A

B=75+A—— eq4

from eq-1 &eq4

B=75-A

(+)B=75+A

——————

2B=150

B=150/2

→B=75°

substitute b=75° in eq-1

75=150-A

A=150-75

→A=75°

Hope it works...........................™✌️✌️