Question

please solve the 3rd and 4th questions ​

Answer 1

Answer:

area of triangle=1/2(ab,*ac)

=1/2(4*4)=8cm²

now again in triangle ABC

using Pythagoras theorem

we get BC=4√2

area of triangle ABC=8cm²

1/2(BC*perpendicular on bc)

1/2(4√2*perpendicular)=8

therefore perpendicular=2√2cm

for 4th

area of triangle=36√3

√3/4*side²=36

SIDE²=36*4

SIDE=12cm

now perimeter=3*side

=3*12

=36cm