please solve the 3rd question
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5x^2 - 22x- 15
=
5x^2+3x-25x-15 = 0
x(5x+3) -5(5x+3) = 0
(x-5) (5x +3)= 0
so,
x=5
x=-3/5
x={5,-3/5}.
By Factorization
By Quadratic solution(a=5,b=-22,C= -15)
discriminant:
b^2-4ac= 484 + 300
= √784
=28
x= -b _+ 28 ÷ 2(5)
= -(-22) _+ 28÷ 10
= 22 _+ 28/10
x = 22 - 28 /10
= -6/10
= -3/10
x = 22+28/10
= 50/10
= 5
so x= { -3/10, 5}
=
5x^2+3x-25x-15 = 0
x(5x+3) -5(5x+3) = 0
(x-5) (5x +3)= 0
so,
x=5
x=-3/5
x={5,-3/5}.
By Factorization
By Quadratic solution(a=5,b=-22,C= -15)
discriminant:
b^2-4ac= 484 + 300
= √784
=28
x= -b _+ 28 ÷ 2(5)
= -(-22) _+ 28÷ 10
= 22 _+ 28/10
x = 22 - 28 /10
= -6/10
= -3/10
x = 22+28/10
= 50/10
= 5
so x= { -3/10, 5}
rohit32194:
thank you friend for helping out this sum
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answer of questions no three in my notebook .please
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