Please solve the 8th questions
Attachments:
Answers
Answered by
1
this is the answer hope u would understand
Attachments:
Answered by
0
let p(x) = ax^3 + x^2 - 2x + b
since (x+1) and (x-1) are the factors of p(x)
p(-1) = 0 and p(1) = 0
p(-1) = a(-1)^3 + (-1)^2 - 2(-1)+b = 0
= -a + 1 +2 + b = 0
a - b=3...(I)
again p(I) = a(1)^3 +(1)^2 -2(1) + b = 0
= a+1-2+b=0
=a+b=1....(ii)
solving equation (I) and (ii) we get a=2 and b= -1
since (x+1) and (x-1) are the factors of p(x)
p(-1) = 0 and p(1) = 0
p(-1) = a(-1)^3 + (-1)^2 - 2(-1)+b = 0
= -a + 1 +2 + b = 0
a - b=3...(I)
again p(I) = a(1)^3 +(1)^2 -2(1) + b = 0
= a+1-2+b=0
=a+b=1....(ii)
solving equation (I) and (ii) we get a=2 and b= -1
Similar questions