please solve the 99and 100 questions
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Q.99 Reciprocal in numerator and using identity in denominator
⇒[ [1 - (b²/a² ] a²] / [ a + b] = 1
⇒[[(a² - b²)/a²]a²] / [ a + b] = 1
⇒[a² - b²] / [ a + b] = 1
⇒ (a - b) (a + b) / (a + b) = 1 ⇒ (a - b) * 5 / 5 = 1
⇒ (a - b) = 1 option a is correct
Q.100
if x + y + z = 0
⇒ √7 - √5 + √5 - √3 + √3 - √7 = 0
then x³ + y³ + z³ = 3xyz
hence x³ + y³ + z³ - 3xyz = 0
option c is correct
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